Matematika Sekolah Menengah Atas 3/4-√3tolong dijawab kk/bg pake jalan besok udah dikumpul​

amparoosinskiulv – April 20, 2023

3/4-√3
tolong dijawab kk/bg pake jalan besok udah dikumpul​

[tex]\frac{3}{4 - \sqrt{3}} = \frac{3}{4 - \sqrt{3}} \times \frac{4 + \sqrt{3}}{4 + \sqrt{3}} = \frac{3 \: (4 + \sqrt{3})}{(4 - \sqrt{3})(4 + \sqrt{3})} [/tex]

[tex]= \frac{12 + 3 \sqrt{3}}{16 + 4 \sqrt{3} - 4 \sqrt{3} - \sqrt{9}} [/tex]

[tex]= \frac{12 + 3 \sqrt{3}}{16 - \sqrt{9}} = \frac{12 + 3 \sqrt{3}}{16 - 3} = \frac{12 + 3 \sqrt{3}}{13} [/tex]

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